document.write( "Question 149521: The surface areas of two cubes are in the ratio of 49:81. If the volume of the smaller cube is 20, what is the volume of the larger cube?
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Algebra.Com's Answer #109702 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! Since the ratio of the surface areas is 49:81, this means that \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now simply take the square root of the fraction to get the ratio of the sides.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the ratio of the sides is 7:9\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now simply cube \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now let x=volume of the larger cube\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since the ratio of the two volumes, this means that we can say\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So our answer is \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the volume of the larger cube is 42.51 \n" ); document.write( " |