document.write( "Question 149517: Find the volume of material that is needed to form a spherical shell whose outer radius is 6.0 inches and whose thickness is 0.01 inches. Use your answer to estimate the surface area of the 6-inch sphere. \n" ); document.write( "
Algebra.Com's Answer #109697 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
First let's find the volume of the outer sphere. Note: I'm going to call this volume \"V%5Bo%5D\"\r
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\n" ); document.write( "\n" ); document.write( "\"V=%284%2F3%29pi%2Ar%5E3\" Start with the volume of a sphere formula.\r
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\n" ); document.write( "\n" ); document.write( "\"V%5Bo%5D=%284%2F3%29pi%2A%286%29%5E3\" Plug in \"r=6\"\r
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\n" ); document.write( "\n" ); document.write( "\"V%5Bo%5D=%284%2F3%29pi%2A%28216%29\" Cube 6 to get 216\r
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\n" ); document.write( "\n" ); document.write( "\"V%5Bo%5D=904.77868\" Multiply.\r
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\n" ); document.write( "\n" ); document.write( "So the volume of the outer sphere is \"V%5Bo%5D=904.77868\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's find the volume of the inner sphere. Since the shell is 0.01 inches thick, this means that the inner radius is \"6-0.01=5.99\" inches.\r
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\n" ); document.write( "\n" ); document.write( " Note: I'm going to call this volume \"V%5Bi%5D\"\r
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\n" ); document.write( "\n" ); document.write( "\"V=%284%2F3%29pi%2Ar%5E3\" Start with the volume of a sphere formula.\r
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\n" ); document.write( "\n" ); document.write( "\"V%5Bi%5D=%284%2F3%29pi%2A%285.99%29%5E3\" Plug in \"r=5.99\"\r
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\n" ); document.write( "\n" ); document.write( "\"V%5Bi%5D=%284%2F3%29pi%2A%28214.92%29\" Cube 5.99 to get 214.92\r
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\n" ); document.write( "\n" ); document.write( "\"V%5Bi%5D=900.26232\" Multiply.\r
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\n" ); document.write( "\n" ); document.write( "So the volume of the inner sphere is \"V%5Bi%5D=900.26232\"\r
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\n" ); document.write( "\n" ); document.write( "So to find the volume of the shell, simply subtract the volume of the inner sphere is \"V%5Bi%5D\" from the volume of the outer sphere is \"V%5Bo%5D\" like this\r
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\n" ); document.write( "\n" ); document.write( "\"V%5Bo%5D-V%5Bi%5D=904.77868-900.26232=4.51636\"\r
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\n" ); document.write( "\n" ); document.write( "So the volume of the shell is about 4.52 cubic inches\r
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\n" ); document.write( "\n" ); document.write( "To find the surface area of the outer sphere, simply use this formula \"A=4pi%2Ar%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"A=4pi%2Ar%5E2\" Start with the surface area formula\r
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\n" ); document.write( "\n" ); document.write( "\"A=4pi%2A%286%29%5E2\" Plug in \"r=6\"\r
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\n" ); document.write( "\n" ); document.write( "\"A=4pi%2A%2836%29\" Square 6 to get 36\r
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\n" ); document.write( "\n" ); document.write( "\"A=144pi\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "So the surface area of the outer sphere is \"A=144pi\" which is approximately 452.39 square inches.\r
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