document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=149484>Question 149484</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A boy rides a bike 8 miles. The trip would have taken 20 minutes less if he had ridden 2 miles per hour faster. find his actual speed. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #109682 by </B><A HREF=/tutors/aboutme.mpl?userid=mangopeeler07><B>mangopeeler07(462)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mangopeeler07><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=109682\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> time=distance/speed\r<BR>\n" );
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document.write( "t=8/s\r<BR>\n" );
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document.write( "t-1/3=8/s+2\r<BR>\n" );
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document.write( "Plug in t\r<BR>\n" );
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document.write( "8/s-1/3=8/s+2\r<BR>\n" );
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document.write( "Common denominator on the left side=3s<BR>\n" );
document.write( "24/3s-s/3s=8/s+2\r<BR>\n" );
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document.write( "Subtract the numerators<BR>\n" );
document.write( "24-s/3s=8/s+2\r<BR>\n" );
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document.write( "Cross multiply<BR>\n" );
document.write( "24s=-s^2+26s+48\r<BR>\n" );
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document.write( "Subtract the 24s from both sides<BR>\n" );
document.write( "0=-s^2+2s+48\r<BR>\n" );
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document.write( "Factor<BR>\n" );
document.write( "0=(-s+8)(s+6)\r<BR>\n" );
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document.write( "Then you solve for s<BR>\n" );
document.write( "s=-6 or 8\r<BR>\n" );
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document.write( "Speed can't be negative, so make them positive<BR>\n" );
document.write( "s=6 or 8\r<BR>\n" );
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document.write( "Plug in 6.<BR>\n" );
document.write( "t=8/6\r<BR>\n" );
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document.write( "t=4/3\r<BR>\n" );
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document.write( "4/3-1/3=8/6+2<BR>\n" );
document.write( "It is true!\r<BR>\n" );
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document.write( "there fore the original speed was 6 mph. </SPAN>\n" );
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