document.write( "Question 149491: Factor the polynomial below completely, given the bionomial folowing it is a factor of thepoynomial x^3-4x^2+x+6, x+1\r
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Algebra.Com's Answer #109670 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! Let's simplify this expression using synthetic division\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Start with the given expression \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "First lets find our test zero:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so our test zero is -1\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now set up the synthetic division table by placing the test zero in the upper left corner and placing the coefficients of the numerator to the right of the test zero.
\n" ); document.write( "\n" ); document.write( "Start by bringing down the leading coefficient (it is the coefficient with the highest exponent which is 1)\r \n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " Multiply -1 by 1 and place the product (which is -1) right underneath the second coefficient (which is -4)\r \n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " Add -1 and -4 to get -5. Place the sum right underneath -1.\r \n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " Multiply -1 by -5 and place the product (which is 5) right underneath the third coefficient (which is 1)\r \n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " Add 5 and 1 to get 6. Place the sum right underneath 5.\r \n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " Multiply -1 by 6 and place the product (which is -6) right underneath the fourth coefficient (which is 6)\r \n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " Add -6 and 6 to get 0. Place the sum right underneath -6.\r \n" ); document.write( "\n" ); document.write( "
\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now lets look at the bottom row of coefficients:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The first 3 coefficients (1,-5,6) form the quotient\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Basically \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now lets break \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Looking at the expression \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now the question is: what two whole numbers multiply to \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "To find these two numbers, we need to list all of the factors of \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Factors of \n" ); document.write( "\n" ); document.write( "1,2,3,6\r \n" ); document.write( "\n" ); document.write( "-1,-2,-3,-6\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Note: list the negative of each factor. This will allow us to find all possible combinations.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to \n" ); document.write( "\n" ); document.write( "1*6 \n" ); document.write( "2*3 \n" ); document.write( "(-1)*(-6) \n" ); document.write( "(-2)*(-3)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now let's add up each pair of factors to see if one pair adds to the middle coefficient \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "From the table, we can see that the two numbers \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the two numbers \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now replace the middle term \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "---------------------------------------------\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer:\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So |