document.write( "Question 149486: Melissa plans to ship a computer in a cubic box that measures x inches on a side. She later determines that her shipping cost will be less if she uses a retanguar box that is 3 inches shorter and 5 inches longer than the cubic box. Write an equation v(x) for the volume of the new box. \n" ); document.write( "
Algebra.Com's Answer #109666 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "The volume of any rectangular box is \"V=L%2AW%2AH\". Since the height is \"3 inches shorter \" and the length is \"5 inches longer than the cubic box\" , this means that the height is \"H=x-3\" and the length is \"L=x-5\". Note: the width remains at \"W=x\"\r
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\n" ); document.write( "\n" ); document.write( "So the volume of the rectangular box is \"V=%28x-5%29%2Ax%2A%28x-3%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"V=%28x-5%29%2Ax%2A%28x-3%29\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"V=x%28x-5%29%28x-3%29\" Rearrange the terms.\r
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\n" ); document.write( "\n" ); document.write( "\"V=x%28x%5E2-8x%2B15%29\" FOIL \"%28x-5%29%28x-3%29\" to get \"x%5E2-8x%2B15\"\r
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\n" ); document.write( "\n" ); document.write( "\"V=x%5E3-8x%5E2%2B15x\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "So the volume of the rectangular box is \"V=x%5E3-8x%5E2%2B15x\"\r
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