document.write( "Question 149464This question is from textbook
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document.write( ": how would i change 1.00x + 0.28(40) = 0.40(x + 40) into a word problem \n" );
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Algebra.Com's Answer #109661 by nabla(475) ![]() You can put this solution on YOUR website! We could say, \n" ); document.write( "x+.28y=.4(x+y) \n" ); document.write( "x+.28y=.4x+.4y \n" ); document.write( "-.12y=-.6x \n" ); document.write( "y=5x \n" ); document.write( "f(x)=5x\r \n" ); document.write( "\n" ); document.write( "Now, for the given, f(x)=40=y gives x=8.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So, this is pretty simplified.\r \n" ); document.write( "\n" ); document.write( "We can say, for example:\r \n" ); document.write( "\n" ); document.write( "Larry needs to purchase as many 2x4s as he can with his $40. Each 2x4 costs $5. How many 2x4s can he buy?\r \n" ); document.write( "\n" ); document.write( "The solution is found by working backward. \n" ); document.write( " |