document.write( "Question 149479: How do yu solve this by using quadratic formula 3x (3x + 4) = -4 ?
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Algebra.Com's Answer #109658 by jim_thompson5910(35256)\"\" \"About 
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\"3x+%283x+%2B+4%29+=+-4\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"9x%5E2+%2B+12x=+-4\" Distribute.\r
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\n" ); document.write( "\n" ); document.write( "\"9x%5E2%2B12x%2B4=0\" Get all terms to the left side.\r
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\n" ); document.write( "\n" ); document.write( "Notice we have a quadratic equation in the form of \"ax%5E2%2Bbx%2Bc\" where \"a=9\", \"b=12\", and \"c=4\"\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for x\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-%2812%29+%2B-+sqrt%28+%2812%29%5E2-4%289%29%284%29+%29%29%2F%282%289%29%29\" Plug in \"a=9\", \"b=12\", and \"c=4\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-12+%2B-+sqrt%28+144-4%289%29%284%29+%29%29%2F%282%289%29%29\" Square \"12\" to get \"144\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-12+%2B-+sqrt%28+144-144+%29%29%2F%282%289%29%29\" Multiply \"4%289%29%284%29\" to get \"144\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-12+%2B-+sqrt%28+0+%29%29%2F%282%289%29%29\" Subtract \"144\" from \"144\" to get \"0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-12+%2B-+sqrt%28+0+%29%29%2F%2818%29\" Multiply \"2\" and \"9\" to get \"18\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-12+%2B-+0%29%2F%2818%29\" Take the square root of \"0\" to get \"0\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-12+%2B+0%29%2F%2818%29\" or \"x+=+%28-12+-+0%29%2F%2818%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-12%29%2F%2818%29\" or \"x+=++%28-12%29%2F%2818%29\" Combine like terms. \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+-2%2F3\" or \"x+=+-2%2F3\" Simplify.\r
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\n" ); document.write( "\n" ); document.write( "So the answer is \"x+=+-2%2F3\" (with a multiplicity of 2).
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