document.write( "Question 149457This question is from textbook
\n" ); document.write( ": The instructions say for each function, find f^-1. Help please, step by step. Thank you...\r
\n" ); document.write( "\n" ); document.write( "f(x)= 6^x-1\r
\n" ); document.write( "\n" ); document.write( "Also, solve each equation. Find the Exact solutions.\r
\n" ); document.write( "\n" ); document.write( "1/2^x = 5 the exponent is above the 2 only.
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Algebra.Com's Answer #109646 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"f%28x%29=+6%5E%28x-1%29+\" Start with the given function.\r
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\n" ); document.write( "\n" ); document.write( "\"x=+6%5E%28f%28x%29-1%29+\" Switch x and f(x).\r
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\n" ); document.write( "\n" ); document.write( "\"log%2810%2C%28x%29%29=+log%2810%2C%286%5E%28f%28x%29-1%29%29%29\" Take the log of both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"log%2810%2C%28x%29%29=+%28f%28x%29-1%29%2Alog%2810%2C%286%29%29\" Rewrite the right side using the identity \"log%28b%2C%28x%5Ey%29%29=y%2Alog%28b%2C%28x%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%2810%2C%28x%29%29=+f%28x%29%2Alog%2810%2C%286%29%29-log%2810%2C%286%29%29\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"log%2810%2C%28x%29%29%2Blog%2810%2C%286%29%29=+f%28x%29%2Alog%2810%2C%286%29%29\" Add \"log%2810%2C%286%29%29\" to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"log%2810%2C%286x%29%29=+f%28x%29%2Alog%2810%2C%286%29%29\" Combine the logs using the identity \"log%28b%2C%28A%29%29%2Blog%28b%2C%28B%29%29=log%28b%2C%28A%2AB%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%2810%2C%286x%29%29%2Flog%2810%2C%286%29%29=+f%28x%29\" Divide both sides by \"log%2810%2C%286%29%29\" to isolate f(x)\r
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\n" ); document.write( "\n" ); document.write( "\"log%286%2C%286x%29%29=+f%28x%29\" Use the change of base formula to rewrite the left side.\r
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\n" ); document.write( "\n" ); document.write( "So the inverse function is \r
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\n" ); document.write( "\n" ); document.write( "\"%281%29%2F%282%5Ex%29+=+5\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"1=+5%282%5Ex%29\" Multiply both sides by \"2%5Ex\".\r
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\n" ); document.write( "\n" ); document.write( "\"1%2F5=2%5Ex\" Divide both sides by \"5\".\r
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\n" ); document.write( "\n" ); document.write( "\"log%2810%2C%281%2F5%29%29=log%2810%2C%282%5Ex%29%29\" Take the log of both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"log%2810%2C%281%2F5%29%29=x%2Alog%2810%2C%282%29%29\" Rewrite the right side using the identity \"log%28b%2C%28x%5Ey%29%29=y%2Alog%28b%2C%28x%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%2810%2C%281%2F5%29%29%2Flog%2810%2C%282%29%29=x\" Divide both sides by \"log%2810%2C%282%29%29\" to isolate x\r
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\n" ); document.write( "\n" ); document.write( "\"log%282%2C%281%2F5%29%29=x\" Use the change of base formula to rewrite the left side.\r
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\n" ); document.write( "\n" ); document.write( "So the answer is \"x=log%282%2C%281%2F5%29%29\" which approximates to \"x=-2.32192\"
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