document.write( "Question 149454: 1)line l goes through (1,3) and is parallel to the line through (4,3) and (-3,1) FInd the slope of l.\r
\n" ); document.write( "\n" ); document.write( "the answer I got was 2/7 is this correct?\r
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\n" ); document.write( "\n" ); document.write( "2)line l goes through the point (5,-2) and is perpendicular to the line through (-2,1)and (-4,-2) Find the slope of l\r
\n" ); document.write( "\n" ); document.write( "the answer I got was -3/2 is this correct?\r
\n" ); document.write( "\n" ); document.write( "3)Write the equation y=1/3x-2 in standard form using only integers and a positive coefficent for x\r
\n" ); document.write( "\n" ); document.write( "The answer I got was x+3y=6 is this correct?\r
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\n" ); document.write( "\n" ); document.write( "4) A Line that goes through (-1,-3)and has a slope of 4.\r
\n" ); document.write( "\n" ); document.write( "My answer is y=4x-3 is this correct?
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Algebra.Com's Answer #109645 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
1) correct\r
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\n" ); document.write( "\n" ); document.write( "2) You're on the right track. The slope through (-2,1)and (-4,-2) is 3/2. So flip the fraction and change the sign to get -2/3. So the perpendicular slope is -2/3\r
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\n" ); document.write( "\n" ); document.write( "3) Close, but you forgot to multiply the term \"3y\" by negative 1 (since you multiplied the \"x\" term by -1). So the correct equation is x-3y=6\r
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\n" ); document.write( "\n" ); document.write( "If you want to find the equation of line with a given a slope of \"4\" which goes through the point (\"-1\",\"-3\"), you can simply use the point-slope formula to find the equation:\r
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\n" ); document.write( "\n" ); document.write( "---Point-Slope Formula---
\n" ); document.write( "\"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where \"m\" is the slope, and is the given point\r
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\n" ); document.write( "\n" ); document.write( "So lets use the Point-Slope Formula to find the equation of the line\r
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\n" ); document.write( "\n" ); document.write( "\"y--3=%284%29%28x--1%29\" Plug in \"m=4\", \"x%5B1%5D=-1\", and \"y%5B1%5D=-3\" (these values are given)\r
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\n" ); document.write( "\n" ); document.write( "\"y%2B3=%284%29%28x--1%29\" Rewrite \"y--3\" as \"y%2B3\"\r
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\n" ); document.write( "\n" ); document.write( "\"y%2B3=%284%29%28x%2B1%29\" Rewrite \"x--1\" as \"x%2B1\"\r
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\n" ); document.write( "\n" ); document.write( "\"y%2B3=4x%2B%284%29%281%29\" Distribute \"4\"\r
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\n" ); document.write( "\n" ); document.write( "\"y%2B3=4x%2B4\" Multiply \"4\" and \"1\" to get \"4\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=4x%2B4-3\" Subtract 3 from both sides to isolate y\r
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\n" ); document.write( "\n" ); document.write( "\"y=4x%2B1\" Combine like terms \"4\" and \"-3\" to get \"1\" \r
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\n" ); document.write( "\n" ); document.write( "So the equation of the line with a slope of \"4\" which goes through the point (\"-1\",\"-3\") is:\r
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\n" ); document.write( "\n" ); document.write( "\"y=4x%2B1\" which is now in \"y=mx%2Bb\" form where the slope is \"m=4\" and the y-intercept is \"b=1\"\r
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\n" ); document.write( "\n" ); document.write( "Notice if we graph the equation \"y=4x%2B1\" and plot the point (\"-1\",\"-3\"), we get (note: if you need help with graphing, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( " Graph of \"y=4x%2B1\" through the point (\"-1\",\"-3\")\r
\n" ); document.write( "\n" ); document.write( "and we can see that the point lies on the line. Since we know the equation has a slope of \"4\" and goes through the point (\"-1\",\"-3\"), this verifies our answer.\r
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