document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=22515>Question 22515</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1.  log6 + Log3 - Log X = Log9<BR>\n" );
document.write( "2.  log 125<BR>\n" );
document.write( "3.  log t<BR>\n" );
document.write( "4.  log 1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #10964 by </B><A HREF=/tutors/aboutme.mpl?userid=ilana><B>ilana(307)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ilana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=10964\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For #1, we can condense this using log properties to log((6*3)/X)=log9.<BR>\n" );
document.write( "We can then take 10^(each side), giving the algebraic equation 18/X=9, so 9X=18, so X=2.\r<BR>\n" );
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document.write( "#2 means 10^X=125.<BR>\n" );
document.write( "#3 means 10^X=t.<BR>\n" );
document.write( "#4 means 10^X=1, so X=log1=0.\r<BR>\n" );
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document.write( "I'm not completely sure what the question is asking of you in 2,3, or 4. </SPAN>\n" );
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