document.write( "Question 149431: In three years, Alex will be 3 times as old as Precy.
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document.write( "A year ago, Alex was 7 times as old as Precy. How old are they now? \n" );
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Algebra.Com's Answer #109634 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! In three years, Alex will be 3 times as old as Precy. \n" ); document.write( "A year ago, Alex was 7 times as old as Precy. How old are they now? \n" ); document.write( ": \n" ); document.write( "Let A and P = their present ages \n" ); document.write( ": \n" ); document.write( "Write an equation for each statement, simplify: \n" ); document.write( ": \n" ); document.write( "\"In three years, Alex will be 3 times as old as Precy.\" \n" ); document.write( "A+3 = 3(P+3) \n" ); document.write( "A + 3 = 3P + 9 \n" ); document.write( "A = 3P + 9 - 3 \n" ); document.write( "A = 3P + 6 \n" ); document.write( ": \n" ); document.write( "\"A year ago, Alex was 7 times as old as Precy.\" \n" ); document.write( "A-1 = 7(P-1) \n" ); document.write( "A - 1 = 7P - 7 \n" ); document.write( "A = 7P - 7 + 1 \n" ); document.write( "A = 7p - 6 \n" ); document.write( ": \n" ); document.write( " How old are they now? \n" ); document.write( ": \n" ); document.write( "Substitute (3P+6) for A in the above equation \n" ); document.write( "3P + 6 = 7p - 6 \n" ); document.write( "6 + 6 = 7P - 3P \n" ); document.write( "12 = 4P \n" ); document.write( "P = \n" ); document.write( "P = 3 yrs old Precy's present age \n" ); document.write( "and \n" ); document.write( "A = 3(3)+ 6 \n" ); document.write( "A = 15 yrs old is Alex's present age \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Check the solution in the statement: \n" ); document.write( "\"A year ago, Alex was 7 times as old as Precy.\" \n" ); document.write( "15 - 1 = 7(3-1) \n" ); document.write( " |