document.write( "Question 149446: need help for solving this expression please. In the book it talking about using the distributive law twice and im not really getting it at all. Here's the problem.
\n" ); document.write( "(x-3)(x+2)
\n" ); document.write( "Any help is greatly appreciated. Thank you. \n" ); document.write( "

Algebra.Com's Answer #109631 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"%28x-3%29%28x%2B2%29\"$
\n" ); document.write( "Let a=(x-3).
\n" ); document.write( " $\"%28x-3%29%28x%2B2%29=a%2A%28x%2B2%29\"$
\n" ); document.write( "Using the distributive property on the right hand side, this becomes,
\n" ); document.write( " $\"%28x-3%29%28x%2B2%29=ax%2B2a%29\"$
\n" ); document.write( "Now substitute for a,
\n" ); document.write( " $\"%28x-3%29%28x%2B2%29=ax%2B2a%29\"$
\n" ); document.write( " $\"%28x-3%29%28x%2B2%29=%28x-3%29x%2B2%28x-3%29%29\"$
\n" ); document.write( "Use the distributive property again on the right hand side,
\n" ); document.write( " $\"%28x-3%29%28x%2B2%29=%28x-3%29x%2B2%28x-3%29%29\"$
\n" ); document.write( " $\"%28x-3%29%28x%2B2%29=%28x%5E2-3x%29%2B%282x-6%29%29\"$
\n" ); document.write( " $\"%28x-3%29%28x%2B2%29=x%5E2-x-6%29\"$
\n" ); document.write( "This is the FOIL Method, in disguise.
\n" ); document.write( "FOIL stands for First, Outer, Inner, Last.
\n" ); document.write( "First $\"%28highlight%28x%29-3%29%28highlight%28x%29%2B2%29%29\"$ = $\"x%2Ax=x%5E2\"$
\n" ); document.write( "Outer $\"%28highlight%28x%29-3%29%28x%2Bhighlight%282%29%29%29\"$ = $\"x%2A2=2x\"$
\n" ); document.write( "First $\"%28x%2Bhighlight%28-3%29%29%28highlight%28x%29%2B2%29%29\"$ = $\"-3%2Ax=-3x\"$
\n" ); document.write( "Last $\"%28x%2Bhighlight%28-3%29%29%28x%2Bhighlight%282%29%29%29\"$ = $\"%28-3%29%2A2=-6\"$
\n" ); document.write( " $\"%28x-3%29%28x%2B2%29=x%5E2%2B2x-3x-6%29\"$
\n" ); document.write( " $\"%28x-3%29%28x%2B2%29=x%5E2-x-6%29\"$ \n" ); document.write( "

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