document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=22516>Question 22516</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Here is my equation:  4^x + 6 = 7<BR>\n" );
document.write( "Here is what I tried: x + 6log4 = 7log<BR>\n" );
document.write( "x (log4 + 6log4) = 7log<BR>\n" );
document.write( "x = 7log/log4 + 6log4<BR>\n" );
document.write( "I come up with 3.61 but I dont think that is correct.  \r<BR>\n" );
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document.write( "Here is the other way I was trying to solve it. <BR>\n" );
document.write( "ln4^x + 6 = ln 7<BR>\n" );
document.write( "x + 6 ln 4 = ln 7<BR>\n" );
document.write( "x = ln7/6ln4 = .45 Is that way correct?   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #10962 by </B><A HREF=/tutors/aboutme.mpl?userid=ilana><B>ilana(307)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ilana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=10962\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Actually, you are making this much more difficult than necessary.  4^x is just a term, so pretend it's 4x for now.  Then we have 4x+6=7.  You then subtarct 6 from both sides to get 4x=1, so x=1/4.  In your problem, begin the same way but get 4^x=1.  (Any number)^0=1, so x=0. </SPAN>\n" );
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