document.write( "Question 149398: Solve the exponential or logarithmic equations. (Write your final answer in BOTH exact and approximate value).\r
\n" ); document.write( "\n" ); document.write( "(a) 6^x-3 = 2^x\r
\n" ); document.write( "\n" ); document.write( "(b) log(5x-6) = 2log x
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Algebra.Com's Answer #109613 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'll do the first one to get you started.\r
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\n" ); document.write( "\n" ); document.write( "\"6%5E%28x-3%29+=+2%5Ex\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"log%2810%2C%286%5E%28x-3%29%29%29+=+log%2810%2C%282%5Ex%29%29\" Take the log of both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-3%29log%2810%2C%286%29%29+=+x%2Alog%2810%2C%282%29%29\" Rewrite both sides using the identity \"log%28b%2C%28x%5Ey%29%29=y%2Alog%28b%2C%28x%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%2Alog%2810%2C%286%29%29-3log%2810%2C%286%29%29+=+x%2Alog%2810%2C%282%29%29\" Distribute.\r
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\n" ); document.write( "\n" ); document.write( "\"x%2Alog%2810%2C%286%29%29-3log%2810%2C%286%29%29-x%2Alog%2810%2C%282%29%29=0\" Subtract \"x%2Alog%2810%2C%282%29%29\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"x%2Alog%2810%2C%286%29%29-x%2Alog%2810%2C%282%29%29=3log%2810%2C%286%29%29\" Add \"3log%2810%2C%286%29%29\" to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"x%28log%2810%2C%286%29%29-log%2810%2C%282%29%29%29=3log%2810%2C%286%29%29\" Factor out the GCF \"x\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%28log%2810%2C%286%2F2%29%29%29=3log%2810%2C%286%29%29\" Combine the logs using the identity \"log%28b%2C%28A%29%29-log%28b%2C%28B%29%29=log%28b%2C%28A%2FB%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%28log%2810%2C%283%29%29%29=3log%2810%2C%286%29%29\" Divide.\r
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\n" ); document.write( "\n" ); document.write( "\"x=3log%2810%2C%286%29%29%2F%28log%2810%2C%283%29%29%29\" Divide both sides by \"log%2810%2C%283%29%29\" to isolate x\r
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\n" ); document.write( "\n" ); document.write( "\"x=log%2810%2C%286%5E3%29%29%2F%28log%2810%2C%283%29%29%29\" Rewrite the expression using the identity \"y%2Alog%28b%2C%28x%29%29=log%28b%2C%28x%5Ey%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=log%2810%2C%28216%29%29%2F%28log%2810%2C%283%29%29%29\" Raise 6 to the 3rd power to get 216\r
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\n" ); document.write( "\n" ); document.write( "\"x=log%283%2C%28216%29%29\" Use the change of base formula to rewrite the right side.\r
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\n" ); document.write( "\n" ); document.write( "So the exact answer is \"x=log%283%2C%28216%29%29\" which approximates to \"x=4.892789\"
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