document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=149398>Question 149398</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the exponential or logarithmic equations. (Write your final answer in BOTH exact and approximate value).\r<BR>\n" );
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document.write( "(a) 6^x-3 = 2^x\r<BR>\n" );
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document.write( "(b) log(5x-6) = 2log x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #109610 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=109610\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (a) 6^x-3 = 2^x <BR>\n" );
document.write( "Take the log of both sides to get:<BR>\n" );
document.write( "(x-3)log6 = xlog2<BR>\n" );
document.write( "x(log6-log2) = 3log6<BR>\n" );
document.write( "x(log3) = 3log6<BR>\n" );
document.write( "x = 3log6/log3<BR>\n" );
document.write( "x = 4.8927...<BR>\n" );
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document.write( "(b) log(5x-6) = 2log x<BR>\n" );
document.write( "log(5x-6) = logx^2<BR>\n" );
document.write( "x^2 = 5x-6<BR>\n" );
document.write( "x^2-5x+6=0<BR>\n" );
document.write( "(x-3)(x-2) = 0<BR>\n" );
document.write( "x = 2 or x = 3\r<BR>\n" );
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document.write( "----------------------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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