document.write( "Question 22506: 
 54x6y-4z2\r\n" );
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document.write( " 9x-3y2z-4
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Algebra.Com's Answer #10961 by AnlytcPhil(1806)\"\" \"About 
You can put this solution on YOUR website!
 54x6y-4z2\r\n" );
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document.write( " 9x-3y2z-4\r\n" );
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document.write( "Rule 1: If a negative exponential is a factor of the numerator,\r\n" );
document.write( "move it from numerator to denominator and change the sign of the\r\n" );
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document.write( "Rule 2: If a negative exponential is a factor of the denominator, \r\n" );
document.write( "move it from denominator to numerator and change the sign of the \r\n" );
document.write( "exponent\r\n" );
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document.write( " 54x6y-4z2\r\n" );
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document.write( " 9x-3y2z-4 \r\n" );
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document.write( "Since the x6 already has a positive exponent, leave it where it is.\r\n" );
document.write( "Move the y-4 to the denominator and change the sign of the -4 \r\n" );
document.write( "exponent to +4\r\n" );
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document.write( "   54x6z2\r\n" );
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document.write( " 9x-3y2z-4y4\r\n" );
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document.write( "Move the x-3 to the numerator and change the sign of the -3 exponent\r\n" );
document.write( "to +3\r\n" );
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document.write( " 54x6z2x3\r\n" );
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document.write( " 9y2z-4y4\r\n" );
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document.write( "Move the z-4 to the numerator and change the sign of the -4 exponent\r\n" );
document.write( "to +4\r\n" );
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document.write( " 54x6z2x3z4\r\n" );
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document.write( "   9y2y4\r\n" );
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document.write( "Now that all exponents are positive, add the exponents of x6 and x3, \r\n" );
document.write( "getting x9\r\n" );
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document.write( "  54x9z2z4\r\n" );
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document.write( "   9y2y4\r\n" );
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document.write( "Add the exponents of z2 and z4, getting z6\r\n" );
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document.write( "  54x9z6\r\n" );
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document.write( "   9y2y4\r\n" );
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document.write( "Add the exponents of y2 and y4, getting y6\r\n" );
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document.write( "  54x9z6\r\n" );
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document.write( "    9y6\r\n" );
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document.write( "Divide the numerator and denominator by 9\r\n" );
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document.write( "  6x9z6\r\n" );
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document.write( "    y6\r\n" );
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document.write( "Edwin\r\n" );
document.write( "AnlytcPhil@aol.com
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