document.write( "Question 149371This question is from textbook Intermediate Algebra with Applications
\n" ); document.write( ": A cyclist rode 40 mi. before having a flat tire and then walking 5 mi to a service station. The cycling rate was four times the walking rate. The time spent cycling and walking was 5 h. Find the rate at which the cyclist was riding. \n" ); document.write( "
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A cyclist rode 40 mi. before having a flat tire and then walking 5 mi to a service station. The cycling rate was four times the walking rate. The time spent cycling and walking was 5 h. Find the rate at which the cyclist was riding.
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\n" ); document.write( "Let x = the walking rate
\n" ); document.write( "then
\n" ); document.write( "4x = the riding rate
\n" ); document.write( ":
\n" ); document.write( "Write a time equation: Time = \"distance%2Frate\"
\n" ); document.write( ":
\n" ); document.write( "Riding time + walking time = 5 hrs
\n" ); document.write( "\"40%2F4x\" + \"5%2Fx\" = 5
\n" ); document.write( "Reduce the fraction:
\n" ); document.write( "\"10%2Fx\" + \"5%2Fx\" = 5
\n" ); document.write( "\"15%2Fx\" = 5
\n" ); document.write( "Multiply both sides by x
\n" ); document.write( "5x = 15
\n" ); document.write( "x = \"15%2F5\"
\n" ); document.write( "x = 3 mph is the walking rate
\n" ); document.write( "then
\n" ); document.write( "4(3) = 12 mph is the riding rate
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\n" ); document.write( ":
\n" ); document.write( "Check solution
\n" ); document.write( "\"40%2F12\" + \"5%2F3\" =
\n" ); document.write( "3\"1%2F3\" + 1\"2%2F3\" = 5 hrs
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