document.write( "Question 149371This question is from textbook Intermediate Algebra with Applications
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document.write( ": A cyclist rode 40 mi. before having a flat tire and then walking 5 mi to a service station. The cycling rate was four times the walking rate. The time spent cycling and walking was 5 h. Find the rate at which the cyclist was riding. \n" );
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Algebra.Com's Answer #109597 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! A cyclist rode 40 mi. before having a flat tire and then walking 5 mi to a service station. The cycling rate was four times the walking rate. The time spent cycling and walking was 5 h. Find the rate at which the cyclist was riding. \n" ); document.write( ": \n" ); document.write( "Let x = the walking rate \n" ); document.write( "then \n" ); document.write( "4x = the riding rate \n" ); document.write( ": \n" ); document.write( "Write a time equation: Time = \n" ); document.write( ": \n" ); document.write( "Riding time + walking time = 5 hrs \n" ); document.write( " \n" ); document.write( "Reduce the fraction: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Multiply both sides by x \n" ); document.write( "5x = 15 \n" ); document.write( "x = \n" ); document.write( "x = 3 mph is the walking rate \n" ); document.write( "then \n" ); document.write( "4(3) = 12 mph is the riding rate \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Check solution \n" ); document.write( " \n" ); document.write( "3 \n" ); document.write( " \n" ); document.write( " |