document.write( "Question 149389: the measure of angle j is half of its compliment plus 12 degrees \n" ); document.write( "

Algebra.Com's Answer #109595 by mangopeeler07(462) $\"\"$ $\"About$

You can put this solution on YOUR website!
j=1/2(c+12)
\n" ); document.write( "c=c\r
\n" ); document.write( "\n" ); document.write( "j+c=90
\n" ); document.write( "1/2(c+12)+c=90\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "1/2c+6+c=90
\n" ); document.write( "3/2c+6=90\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "3/2c=84
\n" ); document.write( "c=55.99\r
\n" ); document.write( "\n" ); document.write( "j=90-c
\n" ); document.write( "j=90-55.99
\n" ); document.write( "j=34.01\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "j=34.01
\n" ); document.write( "j's compliment=55.99\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "------------------------------------OR----------------------------------------
\n" ); document.write( "j=(1/2c)+12
\n" ); document.write( "c=c\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "j+c=90
\n" ); document.write( "1/2c+12+c=90\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "3/2c+12=90
\n" ); document.write( "3/2c=78
\n" ); document.write( "c=52\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "j=38
\n" ); document.write( "j's compliment=52 \n" ); document.write( "

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