document.write( "Question 149374: A plane which can fly 100 miles an hour in still air can fly 500 miles with a wind which is blowing at a certain rate in 5/8 of the time it would require to fly 500 miles against a wind blowing at the same rate. What was the rate of the wind? \n" ); document.write( "
Algebra.Com's Answer #109594 by ankor@dixie-net.com(22740)\"\" \"About 
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A plane which can fly 100 miles an hour in still air can fly 500 miles with a wind which is blowing at a certain rate in 5/8 of the time it would require to fly 500 miles against a wind blowing at the same rate. What was the rate of the wind?
\n" ); document.write( ":
\n" ); document.write( "Let x = the rate of the wind
\n" ); document.write( "then
\n" ); document.write( "(100-x) = speed against the wind
\n" ); document.write( "and
\n" ); document.write( "(100+x) = speed with the wind
\n" ); document.write( ":
\n" ); document.write( "Write a time equation: Time = \"dist%2Fspeed\"
\n" ); document.write( ":
\n" ); document.write( "With the wind time = Against time * \"5%2F8\"
\n" ); document.write( "\"500%2F%28%28100%2Bx%29%29\" = \"500%2F%28%28100-x%29%29\" * \"5%2F8\"
\n" ); document.write( "\"500%2F%28%28100%2Bx%29%29\" = \"2500%2F%288%28100-x%29%29\"
\n" ); document.write( "\"500%2F%28%28100%2Bx%29%29\" = \"2500%2F%28%28800-8x%29%29\"
\n" ); document.write( "Cross multiply:
\n" ); document.write( "2500(100+x) = 500(800-8x)
\n" ); document.write( ":
\n" ); document.write( "250000 + 2500x = 400000 - 4000x
\n" ); document.write( ";
\n" ); document.write( "2500x + 4000x = 400000 - 250000
\n" ); document.write( ":
\n" ); document.write( "6500x = 150000
\n" ); document.write( "x = \"150000%2F6500\"
\n" ); document.write( "x = 23.1 mph, the rate of the wind
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solution, find the time for each trip
\n" ); document.write( "\"500%2F123.1\" = 4.06 hrs
\n" ); document.write( "\"500%2F76.9\" * \"5%2F8\" = 4.06 hr
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