document.write( "Question 149374: A plane which can fly 100 miles an hour in still air can fly 500 miles with a wind which is blowing at a certain rate in 5/8 of the time it would require to fly 500 miles against a wind blowing at the same rate. What was the rate of the wind? \n" ); document.write( "
Algebra.Com's Answer #109594 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A plane which can fly 100 miles an hour in still air can fly 500 miles with a wind which is blowing at a certain rate in 5/8 of the time it would require to fly 500 miles against a wind blowing at the same rate. What was the rate of the wind? \n" ); document.write( ": \n" ); document.write( "Let x = the rate of the wind \n" ); document.write( "then \n" ); document.write( "(100-x) = speed against the wind \n" ); document.write( "and \n" ); document.write( "(100+x) = speed with the wind \n" ); document.write( ": \n" ); document.write( "Write a time equation: Time = \n" ); document.write( ": \n" ); document.write( "With the wind time = Against time * \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Cross multiply: \n" ); document.write( "2500(100+x) = 500(800-8x) \n" ); document.write( ": \n" ); document.write( "250000 + 2500x = 400000 - 4000x \n" ); document.write( "; \n" ); document.write( "2500x + 4000x = 400000 - 250000 \n" ); document.write( ": \n" ); document.write( "6500x = 150000 \n" ); document.write( "x = \n" ); document.write( "x = 23.1 mph, the rate of the wind \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution, find the time for each trip \n" ); document.write( " \n" ); document.write( " |