document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=22453>Question 22453</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can anyone help with this?\r<BR>\n" );
document.write( "\n" );
document.write( "[In times the cuberoot of e^2] [log 125 to the base of 5]<BR>\n" );
document.write( "I did:<BR>\n" );
document.write( "[In(e^2)^1/3] [log 5^3 to the base of 5]<BR>\n" );
document.write( "[In e^2/3] [3log 5 to the base of 5]<BR>\n" );
document.write( "[1^2/3] [3(1)]<BR>\n" );
document.write( "the cube root of 1^2(3)\r<BR>\n" );
document.write( "\n" );
document.write( "the answer is 2, what did I do wrong and/or how do I finish?\r<BR>\n" );
document.write( "\n" );
document.write( "thanks,<BR>\n" );
document.write( "Sandy </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #10953 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=10953\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You did fine.<BR>\n" );
document.write( "You have [In e^2/3] [3log 5 to the base of 5]<BR>\n" );
document.write( "ln e^(2/3) is (2/3)<BR>\n" );
document.write( "3log 5 (base 5) is 3(1)=3<BR>\n" );
document.write( "So you have (2/3)(3)= 2\r<BR>\n" );
document.write( "\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );