document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=149251>Question 149251</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a paper towel tube has a diameter of 1.7 inches and a height of 11 inches.  If the tube were cut and unfolded to form a rectangle, what would be the area of the rectangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #109503 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=109503\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The \"width\" of the rectangle would be the \"circumference\" of the tube whereas the length is merely the height of the tube.<BR>\n" );
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document.write( "Therefore, we have:<BR>\n" );
document.write( "length = 11 inches<BR>\n" );
document.write( "width = 2(pi)r = 2(3.14)(1.7) = 2(3.14)(1.7/2)<BR>\n" );
document.write( "width = (3.14)(1.7)<BR>\n" );
document.write( ".<BR>\n" );
document.write( "area of rectangle = length * width<BR>\n" );
document.write( "area of rectangle = 11(3.14)(1.7) = 58.718 square inches<BR>\n" );
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