document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=149085>Question 149085</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm not sure if this problem is in the right section, but my teacher says that this problem pertains to real numbers.\r<BR>\n" );
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document.write( "Find a value of  \"y\"  for which the expression  \"(1 - y)(3 - y)(6 - y) = 18\" becomes true.\r<BR>\n" );
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document.write( "Many thanks in advance. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #109490 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=109490\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y = 0<BR>\n" );
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document.write( "To check, plug it back in:<BR>\n" );
document.write( "(1 - y)(3 - y)(6 - y) = 18<BR>\n" );
document.write( "(1 - 0)(3 - 0)(6 - 0) = 18<BR>\n" );
document.write( "(1)(3)(6) = 18<BR>\n" );
document.write( "18 = 18<BR>\n" );
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