document.write( "Question 149208: An express and local train leave Gray's Lake at 3PM and head for Chicago 50 miles away. The express travels twice as fast as the local and arrive 1 hour ahead of it. Find the speed of each train. \n" ); document.write( "

Algebra.Com's Answer #109470 by mangopeeler07(462) $\"\"$ $\"About$

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2x=express speed
\n" ); document.write( "x=local speed
\n" ); document.write( "50=miles\r
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\n" ); document.write( "\n" ); document.write( "50/2x=(50/x)-1\r
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\n" ); document.write( "\n" ); document.write( "Common denominator=2x
\n" ); document.write( "50/2x=100/2x-2x/2x\r
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\n" ); document.write( "\n" ); document.write( "Eliminate the denominator
\n" ); document.write( "50=100-2x\r
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\n" ); document.write( "\n" ); document.write( "Subtract 100 from both sides
\n" ); document.write( "-50=-2x\r
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\n" ); document.write( "\n" ); document.write( "Divide by -2
\n" ); document.write( "25=x\r
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\n" ); document.write( "\n" ); document.write( "2x=express speed
\n" ); document.write( "x=local speed\r
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\n" ); document.write( "\n" ); document.write( "Local train: 25mph
\n" ); document.write( "Express train: 50mph \n" ); document.write( "

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