document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=149195>Question 149195</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help desperately on these questions. They need to be expressed in lowest terms. Can you help me with these. I have the answer to a few but I am unaware as to if they are right and if not how would I successfully express these in lowest form. \r<BR>\n" );
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document.write( "1) x/x+xy\r<BR>\n" );
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document.write( "=y\r<BR>\n" );
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document.write( "is this correct?\r<BR>\n" );
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document.write( "2)3x^2+6x/3x^2+9x\r<BR>\n" );
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document.write( "=6/9=2/3 is this correct?\r<BR>\n" );
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document.write( "3)x^2+2x+1/x+1\r<BR>\n" );
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document.write( "4)x^2+3x-18/2x-6\r<BR>\n" );
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document.write( "5)2x^2-4x-6/x-3 <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #109458 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=109458\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1) x/x+xy<BR>\n" );
document.write( "=y<BR>\n" );
document.write( "is this correct? NO<BR>\n" );
document.write( "To combine, both terms need to have the same denominator.<BR>\n" );
document.write( "x/x + xy<BR>\n" );
document.write( "= x/x + x^2y/x<BR>\n" );
document.write( "= (x+x^2y)/x<BR>\n" );
document.write( "= [x(1+xy)]/x<BR>\n" );
document.write( "= 1+xy<BR>\n" );
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document.write( "2)3x^2+6x/3x^2+9x<BR>\n" );
document.write( "=6/9=2/3 is this correct? NO<BR>\n" );
document.write( "I'll assume your original problem is:<BR>\n" );
document.write( "(3x^2+6x)/(3x^2+9x)  (correct me if I'm wrong)<BR>\n" );
document.write( "Now, you \"factor\" the numerator and denominator to get:<BR>\n" );
document.write( "[3x(x+2)]/[3x(x+3)]<BR>\n" );
document.write( "= (x+2)/(x+3)<BR>\n" );
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document.write( "3)x^2+2x+1/x+1<BR>\n" );
document.write( "I'll assume your original problem is:<BR>\n" );
document.write( "(x^2+2x+1)/(x+1)<BR>\n" );
document.write( "Factoring the numerator we get:<BR>\n" );
document.write( "[(x+1)(x+1)]/(x+1)<BR>\n" );
document.write( "= x+1<BR>\n" );
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document.write( "4)x^2+3x-18/2x-6<BR>\n" );
document.write( "I'll assume your original problem is:<BR>\n" );
document.write( "(x^2+3x-18)/(2x-6)<BR>\n" );
document.write( "Factoring we get:<BR>\n" );
document.write( "[(x-3)(x+6)]/[2(x-3)]<BR>\n" );
document.write( "= x+6<BR>\n" );
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document.write( "5)2x^2-4x-6/x-3 <BR>\n" );
document.write( "I'll assume your original problem is:<BR>\n" );
document.write( "(2x^2-4x-6)/(x-3)<BR>\n" );
document.write( "= [2(x^2-2x-3)]/(x-3)<BR>\n" );
document.write( "= [2(x-3)(x+1)]/(x-3)<BR>\n" );
document.write( "= 2(x+1)<BR>\n" );
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