document.write( "Question 149202: Marcus saved 20 coins consisting of 25 cents and Php 1 coins. How many of each kind did he have if the coins amounted to Php 10.25? \n" ); document.write( "

Algebra.Com's Answer #109457 by jojo14344(1513) $\"\"$ $\"About$

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Let \"x\" = P 0.25
\n" ); document.write( "\"y\" = P 1.00
\n" ); document.write( "We know we have 20 coins in total, so $\"x%2By=20\"$ right? -----> eqn 1
\n" ); document.write( "Also, 0.25x + 1.00y = P 10.25 -------> eqn 2
\n" ); document.write( "In eqn 1, we get $\"y=20-x\"$ and substitute it in eqn 2,
\n" ); document.write( "Continuing,
\n" ); document.write( "0.25x + 1.00(20-x) =10.25
\n" ); document.write( "0.25x + 20 - 1x = 10.25
\n" ); document.write( "re-arranging, 20-10.25 = x-0.25x
\n" ); document.write( "0.75x = 9.75
\n" ); document.write( " $\"x=13\"$ ------------> no. of P 0.25 coins
\n" ); document.write( "In eqn 1, $\"13+%2B+y+=20\"$ , $\"y=7\"$ -----> no. of P1.00
\n" ); document.write( "In doubt? Go back eqn 2,
\n" ); document.write( "(0.25*13) + (1*7) = 10.25
\n" ); document.write( "3.25 + 7 = 10.25
\n" ); document.write( "P10.25=P10.25
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo \n" ); document.write( "

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