document.write( "Question 149190: how to solve this equation x+y<5 x-y>1 by using the graphs of linear inequalities
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Algebra.Com's Answer #109451 by vleith(2983)\"\" \"About 
You can put this solution on YOUR website!
Plot the two lines - don't worry about the inequality yet
\n" ); document.write( "\"x+%2B+y+=+5\"
\n" ); document.write( "\"y+=+-x+%2B+5\"\r
\n" ); document.write( "\n" ); document.write( "\"x+-+y+=+1\"
\n" ); document.write( "\"y+=+x+-+1\"\r
\n" ); document.write( "\n" ); document.write( "\"graph%28600%2C400%2C+-10%2C+10%2C+-10%2C+10%2C+-x+%2B+5%2C+x+-+1%29\"\r
\n" ); document.write( "\n" ); document.write( "As you can see, the two lines cut the plane into 4 pieces. \r
\n" ); document.write( "\n" ); document.write( "Now let's look at the inequalities again.
\n" ); document.write( "\"x+%2B+y+%3C+5\"
\n" ); document.write( "\"y+%3C+-x+%2B+5\"
\n" ); document.write( "Since this equation does NOT include an equality, draw the line that is sloping downward (the slope for this line = -1) using a dashed line.
\n" ); document.write( "Next, since the inequality is < (less than), shade the area BELOW that line.\r
\n" ); document.write( "\n" ); document.write( "Do the same steps for the other line.
\n" ); document.write( "\"x+-+y+%3E+1\"
\n" ); document.write( "\"y+%3E+x+-+1\"
\n" ); document.write( "Since this equation does NOT include an equality, draw the line that is sloping upward (the slope for this line = 1) using a dashed line.
\n" ); document.write( "Next, since the inequality is > (greater than), shade the area ABOVE that line.\r
\n" ); document.write( "\n" ); document.write( "The answer is the area that is shaded by both. So, the area that is both BELOW the first line and also ABOVE the second line.\r
\n" ); document.write( "\n" ); document.write( "Remember to use dashed lines. \r
\n" ); document.write( "\n" ); document.write( "If you look at the plot as the letter X, the area you want is to the left of the X and NOT including the lines that make the X
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