document.write( "Question 149109: Factor completely\r
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document.write( "1)x^3-6x^2+11x-6 given that x-1 is a factor\r
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document.write( "2)x^2+6x+9=0\r
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document.write( "3)2x^2+5x-12=0\r
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document.write( "4)3x^3=12x\r
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document.write( "5)(2x-1)(3x+5)=5
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Algebra.Com's Answer #109447 by edjones(8007)![]() ![]() You can put this solution on YOUR website! 1) \n" ); document.write( "(x^3-6x^2+11x-6)/(x-1) Long division or synthetic division. \n" ); document.write( "=x^2-5x+6 \n" ); document.write( "=(x-3)(x-2) \n" ); document.write( ". \n" ); document.write( "2) \n" ); document.write( "x^2+6x+9=0 \n" ); document.write( "(x+3)^2=0 \n" ); document.write( "x=-3 \n" ); document.write( ". \n" ); document.write( "3) \n" ); document.write( "2x^2+5x-12=0 \n" ); document.write( "2*-12=-24... 8 and -3 are factors of -24 that when added equal 5. \n" ); document.write( "2x^2+8x-3x-12=0 \n" ); document.write( "2x(x+4)-3(x+4)=0 \n" ); document.write( "(2x-3)(x+4)=0 \n" ); document.write( "2x=3 \n" ); document.write( "x=3/2 \n" ); document.write( "x=-4 \n" ); document.write( ". \n" ); document.write( "4) \n" ); document.write( "3x^3=12x \n" ); document.write( "3x^3-12x=0 \n" ); document.write( "3x(x^2-4)=0 \n" ); document.write( "3x(x+2)(x-2)=0 \n" ); document.write( "x=0, x=-2, x=2 \n" ); document.write( ". \n" ); document.write( "5) \n" ); document.write( "(2x-1)(3x+5)=5 \n" ); document.write( "6x^2+7x-5=5 \n" ); document.write( "6x^2+7x-10=0 \n" ); document.write( "6*-10=-60... 12 and -5 are factors of -60 whose sum is 7. \n" ); document.write( "6x^2+12x-5x-10=0 \n" ); document.write( "6x(x+2)-5(x+2)=0 \n" ); document.write( "(6x-5)(x+2)=0 \n" ); document.write( "6x=5 \n" ); document.write( "x=5/6 \n" ); document.write( "x=-2 \n" ); document.write( ". \n" ); document.write( "Ed\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |