document.write( "Question 149142: Find the solution by substitution:
\n" ); document.write( "4x+3y=5
\n" ); document.write( "2x-y=-5
\n" ); document.write( "

Algebra.Com's Answer #109400 by mangopeeler07(462)\"\" \"About 
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4x+3y=5
\n" ); document.write( "2x-y=-5\r
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\n" ); document.write( "\n" ); document.write( "Solve for y in the second equation:
\n" ); document.write( "2x-y=-5
\n" ); document.write( "-y=-2x-5
\n" ); document.write( "y=2x+5\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Plug that into the first equation
\n" ); document.write( "4x+3y=5
\n" ); document.write( "4x+3(2x+5)=5
\n" ); document.write( "4x+6x+15=5
\n" ); document.write( "10x+15=5
\n" ); document.write( "10x=-10
\n" ); document.write( "x=-1\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Plug that into y=2x+5
\n" ); document.write( "y=2(-1)+5
\n" ); document.write( "y=-2+5
\n" ); document.write( "y=3\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So,
\n" ); document.write( "x=-1
\n" ); document.write( "y=3
\n" ); document.write( "
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