document.write( "Question 149114: please help!!!\r
\n" ); document.write( "\n" ); document.write( "the robinson track is shpaed like a rectangle with a semicircle on each of the shorter sies. the distance around the track is 1/4 mile. the straightaway is twice as long as the width of the field. what is the area of the field enclosed by the track to the nearest square foot?\r
\n" ); document.write( "\n" ); document.write( "thank you sooo much !
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Algebra.Com's Answer #109386 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Call the straight part of the track \"s\"
\n" ); document.write( "Call the width \"w\"
\n" ); document.write( "Adding up the stright parts on each side, \"s+%2B+s+=+2s\"
\n" ); document.write( "The straightaway is twice the width
\n" ); document.write( "\"s+=+2w\"
\n" ); document.write( "\"w+=+%281%2F2%29%2As\"
\n" ); document.write( "The circular portions of the track are made up of
\n" ); document.write( "1/2 the circumference of a circle with diameter = \"w\" on
\n" ); document.write( "one end and another 1/2 of a circumference with diameter = \"w\"
\n" ); document.write( "on the other end of the track
\n" ); document.write( "If circumference = \"C\",
\n" ); document.write( "\"%281%2F2%29%2AC+%2B+%281%2F2%29%2AC+=+C\"
\n" ); document.write( "also,
\n" ); document.write( "\"C+=+pi%2Aw\"
\n" ); document.write( "\"C+=+3.1416%2A%281%2F2%29%2As\"
\n" ); document.write( "\"C+=+1.571s\"
\n" ); document.write( "\"1.571s+%2B+2s+=+.25\"mi
\n" ); document.write( "1 mi = 5280 ft
\n" ); document.write( "\"3.571s+=+.25+%2A+5280\"
\n" ); document.write( "\"s+=+369.6\" ft
\n" ); document.write( "The area of the track is made up of a rectangle \"s%2Aw\"
\n" ); document.write( "and 2 half-circles which add up to a whole circle,
\n" ); document.write( "area = \"pi%2A%28w%2F2%29%5E2\"
\n" ); document.write( "\"pi%2A%28s%2F4%29%5E2\"
\n" ); document.write( "\"%283.1416+%2F+16%29%2A%28369.6%29%5E2\"
\n" ); document.write( "\".196%2A136604.16\"
\n" ); document.write( "\"26774.42\"
\n" ); document.write( "The area of the rectangular part is \"s%2Aw\"
\n" ); document.write( "\"369.6%2A%28369.6%2F2%29\"
\n" ); document.write( "\"68302.08\"
\n" ); document.write( "The total area is
\n" ); document.write( "\"26774.42+%2B+68302.08+=+95076.5\"
\n" ); document.write( "The area of the field to the nearest ft2 is 95,077 ft2
\n" ); document.write( "check my work- I could have made a mistake, but I hope
\n" ); document.write( "you get my method
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