document.write( "Question 149108: Bob is half as old as Tom.\r
\n" ); document.write( "\n" ); document.write( "One year ago Bob age was two fifths of what Tom's age will be a year from now.\r
\n" ); document.write( "\n" ); document.write( "Can you figure out Bob's age and Tom's age. \n" ); document.write( "

Algebra.Com's Answer #109381 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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Write an equation for each statement:
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\n" ); document.write( "\"Bob is half as old as Tom.\"
\n" ); document.write( "B = $\"1%2F2\"$ T
\n" ); document.write( "or
\n" ); document.write( "T = 2B
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\n" ); document.write( "\"One year ago Bob age was two fifths of what Tom's age will be a year from now.\"
\n" ); document.write( "B - 1 = $\"2%2F5\"$ (T + 1)
\n" ); document.write( "Multiply equation by 5 to get rid of the denominator, results:
\n" ); document.write( "5(B - 1) = 2(T + 1)
\n" ); document.write( ":
\n" ); document.write( "5B - 5 = 2T + 2
\n" ); document.write( ":
\n" ); document.write( "5B = 2T + 2 + 5
\n" ); document.write( ":
\n" ); document.write( "5B = 2T + 7
\n" ); document.write( ":
\n" ); document.write( "Can you figure out Bob's age and Tom's age.
\n" ); document.write( ":
\n" ); document.write( "Substitute 2B for T in the above equation
\n" ); document.write( "5B = 2(2B) + 7
\n" ); document.write( "5B = 4B + 7
\n" ); document.write( "5B - 4B = 7
\n" ); document.write( "B = 7 yrs is Bob's age
\n" ); document.write( "Then
\n" ); document.write( "T = 2(7)
\n" ); document.write( "T = 14 yrs is Tom's age
\n" ); document.write( ":
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\n" ); document.write( "Check solution using the statement:
\n" ); document.write( "\"One year ago Bob age was two fifths of what Tom's age will be a year from now.\"
\n" ); document.write( "7 - 1 = $\"2%2F5\"$ (14 + 1)
\n" ); document.write( "6 = $\"2%2F5\"$ *15 \n" ); document.write( "

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