document.write( "Question 149100: An express and local train leave gray's lake at 3 P.M. and head for chicago 50 miles away. The express travels twice as fast as the local and arrives 1 hour ahead of it. Find the speed of each train. \n" ); document.write( "
Algebra.Com's Answer #109378 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! an express and local train leave Gray's Lake at 3 P.M. and head for Chicago 50 miles away. The express travels twice as fast as the local, and arrives 1 hour ahead of it. Find the speed of each train. \n" ); document.write( ": \n" ); document.write( "The time they left is irrelevant to the problem \n" ); document.write( ": \n" ); document.write( "Let s = speed of the local \n" ); document.write( "then \n" ); document.write( "2s = speed of the express \n" ); document.write( ": \n" ); document.write( "Write a time equation: Time = \n" ); document.write( ": \n" ); document.write( "Express time + 1 hr = Local time \n" ); document.write( " \n" ); document.write( "Get rid of the denominators, mult equation by 2s; results: \n" ); document.write( "50 + 2s = 2(50) \n" ); document.write( "2s = 100 - 50 \n" ); document.write( "2s = 50 \n" ); document.write( "s = \n" ); document.write( "s = 25 mph speed of the local \n" ); document.write( "then \n" ); document.write( "50 mph speed of the express \n" ); document.write( "; \n" ); document.write( "; \n" ); document.write( "Check solution \n" ); document.write( " \n" ); document.write( "1 + 1 = 2 \n" ); document.write( " |