document.write( "Question 149079: installing a dishwasher. A plumber can install a dishwasher in 50 minutes. If the plumber brings his apprentice, the job takes 40 minutes. How long would it take the apprentice working alone to install the dishwasher? \n" ); document.write( "
Algebra.Com's Answer #109367 by solver91311(24713)\"\" \"About 
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If the plumber can do the installation in 50 minutes, then he can do \"1%2F50\" of the installation in 1 minute. Likewise, working together, the plumber and his apprentice can do \"1%2F40\" of the job in a minute. We need to find out how many minutes it takes the apprentice by himself and we'll call that \"x\", so the apprentice by himself can do \"1%2Fx\" of the job in one minute. So we can write:\r
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\n" ); document.write( "\n" ); document.write( "\"1%2F50%2B1%2Fx=1%2F40\"\r
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\n" ); document.write( "\n" ); document.write( "\"1%2Fx=1%2F40-1%2F50\"\r
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\n" ); document.write( "\n" ); document.write( "LCD for 40 and 50 would be 200, so:\r
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\n" ); document.write( "\n" ); document.write( "\"1%2Fx=5%2F200-4%2F200\"\r
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\n" ); document.write( "\n" ); document.write( "\"1%2Fx=1%2F200\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=200\"\r
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\n" ); document.write( "\n" ); document.write( "So it would take the apprentice 200 minutes or 3 hours and 20 minutes to do the installation by himself (presuming, of course, that the apprentice could do it by himself at all).
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