document.write( "Question 149089: How do I put this word problem into a quadratic equation or set it up?\r
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document.write( "An express and local train leave Gray’s Lake at 3 P.M. and head for Chicago 50 miles away. The express travels twice as fast as the local, and arrives 1 hour ahead of it. Find the speed of each train.
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document.write( "I know that distance equals rate times time but on all else I am confused to say the least. Any info you can offer will be greatly appreciated. \n" );
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Algebra.Com's Answer #109358 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! an express and local train leave Gray's Lake at 3 P.M. and head for Chicago 50 miles away. The express travels twice as fast as the local, and arrives 1 hour ahead of it. Find the speed of each train. \n" ); document.write( ": \n" ); document.write( "The time they left is irrelevant to the problem \n" ); document.write( ": \n" ); document.write( "Let s = speed of the local \n" ); document.write( "then \n" ); document.write( "2s = speed of the express \n" ); document.write( ": \n" ); document.write( "Write a time equation: Time = \n" ); document.write( ": \n" ); document.write( "Express time + 1 hr = Local time \n" ); document.write( " \n" ); document.write( "Get rid of the denominators, mult equation by 2s; results: \n" ); document.write( "50 + 2s = 2(50) \n" ); document.write( "2s = 100 - 50 \n" ); document.write( "2s = 50 \n" ); document.write( "s = \n" ); document.write( "s = 25 mph speed of the local \n" ); document.write( "then \n" ); document.write( "50 mph speed of the express \n" ); document.write( "; \n" ); document.write( "; \n" ); document.write( "Check solution \n" ); document.write( " \n" ); document.write( "1 + 1 = 2 \n" ); document.write( " |