document.write( "Question 149008: 1. The ratio of two numbers in 6:1.If their difference is 35, what is the smaller number?
\n" ); document.write( "2. The ratio of the width to the length of a rectangle is 2:3. If the area of the rectanglle is 216 sq. cm. , what is its width?\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #109357 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
1. The ratio of two numbers in 6:1.If their difference is 35, what is the smaller number?
\n" ); document.write( ":
\n" ); document.write( "Let x= a number; y = smaller number
\n" ); document.write( "Write an equation for each statement
\n" ); document.write( "\"The ratio of two numbers in 6:1\"
\n" ); document.write( "\"x%2Fy\"=\"6%2F1\"
\n" ); document.write( ":
\n" ); document.write( "\"If their difference is 35,\"
\n" ); document.write( "x - y = 35
\n" ); document.write( "x = y + 35
\n" ); document.write( ":
\n" ); document.write( "what is the smaller number?
\n" ); document.write( "Substitute (y+35) for x in the ratio equation:
\n" ); document.write( "\"%28%28y%2B35%29%29%2Fy\" = \"6%2F1\"
\n" ); document.write( "Cross multiply
\n" ); document.write( "y + 35 = 6y
\n" ); document.write( "35 = 6y - y
\n" ); document.write( "35 = 5y
\n" ); document.write( "y = \"35%2F5\"
\n" ); document.write( "y = 7 is the smaller number
\n" ); document.write( ":
\n" ); document.write( "Check: larger number would be 7 + 35 = 42, we can see that:
\n" ); document.write( "\"42%2F7\" = \"6%2F1\"
\n" ); document.write( ";
\n" ); document.write( ":
\n" ); document.write( "2. The ratio of the width to the length of a rectangle is 2:3. If the area of the rectangle is 216 sq. cm. , what is its width?
\n" ); document.write( ":
\n" ); document.write( "Write an equation for each statement:
\n" ); document.write( "\"W%2FL\" = \"2%2F3\"
\n" ); document.write( "and
\n" ); document.write( "L * W = 216
\n" ); document.write( "L = \"216%2FW\"
\n" ); document.write( ":
\n" ); document.write( "Substitute (216/W) for L in the ratio equation
\n" ); document.write( "\"W%2F%28%28216%2FW%29%29\" = \"2%2F3\"
\n" ); document.write( "Cross multiply
\n" ); document.write( "3W = 2*\"216%2FW\"
\n" ); document.write( "3W = \"432%2FW\"
\n" ); document.write( "Multiply both sides by W, get rid of the denominator and you have:
\n" ); document.write( "3W^2 = 432
\n" ); document.write( ":
\n" ); document.write( "W^2 = \"432%2F3\"
\n" ); document.write( "W^2 = 144
\n" ); document.write( "W = \"sqrt%28144%29\", find the square root of both sides
\n" ); document.write( "W = 12 cm is the width
\n" ); document.write( ":
\n" ); document.write( "Check solution
\n" ); document.write( "L = 216/12 = 18 cm
\n" ); document.write( ":
\n" ); document.write( "\"12%2F18\" = \"2%2F3\" confirms our solution
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Did this make sense to you? Any questions?
\n" ); document.write( "
\n" );