document.write( "Question 149008: 1. The ratio of two numbers in 6:1.If their difference is 35, what is the smaller number?
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document.write( "2. The ratio of the width to the length of a rectangle is 2:3. If the area of the rectanglle is 216 sq. cm. , what is its width?\r
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Algebra.Com's Answer #109357 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! 1. The ratio of two numbers in 6:1.If their difference is 35, what is the smaller number? \n" ); document.write( ": \n" ); document.write( "Let x= a number; y = smaller number \n" ); document.write( "Write an equation for each statement \n" ); document.write( "\"The ratio of two numbers in 6:1\" \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "\"If their difference is 35,\" \n" ); document.write( "x - y = 35 \n" ); document.write( "x = y + 35 \n" ); document.write( ": \n" ); document.write( "what is the smaller number? \n" ); document.write( "Substitute (y+35) for x in the ratio equation: \n" ); document.write( " \n" ); document.write( "Cross multiply \n" ); document.write( "y + 35 = 6y \n" ); document.write( "35 = 6y - y \n" ); document.write( "35 = 5y \n" ); document.write( "y = \n" ); document.write( "y = 7 is the smaller number \n" ); document.write( ": \n" ); document.write( "Check: larger number would be 7 + 35 = 42, we can see that: \n" ); document.write( " \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "2. The ratio of the width to the length of a rectangle is 2:3. If the area of the rectangle is 216 sq. cm. , what is its width? \n" ); document.write( ": \n" ); document.write( "Write an equation for each statement: \n" ); document.write( " \n" ); document.write( "and \n" ); document.write( "L * W = 216 \n" ); document.write( "L = \n" ); document.write( ": \n" ); document.write( "Substitute (216/W) for L in the ratio equation \n" ); document.write( " \n" ); document.write( "Cross multiply \n" ); document.write( "3W = 2* \n" ); document.write( "3W = \n" ); document.write( "Multiply both sides by W, get rid of the denominator and you have: \n" ); document.write( "3W^2 = 432 \n" ); document.write( ": \n" ); document.write( "W^2 = \n" ); document.write( "W^2 = 144 \n" ); document.write( "W = \n" ); document.write( "W = 12 cm is the width \n" ); document.write( ": \n" ); document.write( "Check solution \n" ); document.write( "L = 216/12 = 18 cm \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Did this make sense to you? Any questions? \n" ); document.write( " |