document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=149036>Question 149036</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If x=1 and x= -8, then form a quadratic equation </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #109343 by </B><A HREF=/tutors/aboutme.mpl?userid=mangopeeler07><B>mangopeeler07(462)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mangopeeler07><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=109343\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> in a quadratic equation, for x, you solve for the value that would make an expression zero.  So if x=1 and x= -8, just move backwards.  \r<BR>\n" );
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document.write( "For positive x's<BR>\n" );
document.write( "(x-b)=0<BR>\n" );
document.write( "For negative x's<BR>\n" );
document.write( "(x+b)=0\r<BR>\n" );
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document.write( "plug in your x's<BR>\n" );
document.write( "(1-b)=0<BR>\n" );
document.write( "(-8+b)=0\r<BR>\n" );
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document.write( "Solve for b's<BR>\n" );
document.write( "b=1<BR>\n" );
document.write( "b=8\r<BR>\n" );
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document.write( "So the original equation was<BR>\n" );
document.write( "(x-1)(x+8)=0 </SPAN>\n" );
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