document.write( "Question 149034: A total of $3.45 constisting of dimes and quarters was collected from a soft drink vending machine. If there are 3 more dimes than quarters, find the numnber of dimes and quarters. \n" ); document.write( "
Algebra.Com's Answer #109342 by mangopeeler07(462)\"\" \"About 
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d=number of dimes
\n" ); document.write( "q=number of quarters
\n" ); document.write( "coefficient=value of the coin\r
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\n" ); document.write( "\n" ); document.write( "10d+25q=345--------------------because the total value of both the coins is 345 cents
\n" ); document.write( "d=q+3--------------------------because there are 3 more dimes than quarters\r
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\n" ); document.write( "\n" ); document.write( "Plug d into the first equation
\n" ); document.write( "10(q+3)+25q=345\r
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\n" ); document.write( "\n" ); document.write( "Distribute
\n" ); document.write( "10q+30+25q=345\r
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\n" ); document.write( "\n" ); document.write( "Combine like terms
\n" ); document.write( "35q+30=345\r
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\n" ); document.write( "\n" ); document.write( "Subtract 30 from both sides
\n" ); document.write( "35q=315\r
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\n" ); document.write( "\n" ); document.write( "Divide both sides by 35
\n" ); document.write( "q=9\r
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\n" ); document.write( "\n" ); document.write( "Number of quarters=9\r
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\n" ); document.write( "\n" ); document.write( "d=q+3
\n" ); document.write( "d=9+3
\n" ); document.write( "d=12\r
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\n" ); document.write( "\n" ); document.write( "number of dimes=12\r
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\n" ); document.write( "\n" ); document.write( "So,
\n" ); document.write( "number or quarters=9
\n" ); document.write( "number of dimes=12
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