document.write( "Question 149034: A total of $3.45 constisting of dimes and quarters was collected from a soft drink vending machine. If there are 3 more dimes than quarters, find the numnber of dimes and quarters. \n" ); document.write( "
Algebra.Com's Answer #109342 by mangopeeler07(462)![]() ![]() ![]() You can put this solution on YOUR website! d=number of dimes \n" ); document.write( "q=number of quarters \n" ); document.write( "coefficient=value of the coin\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "10d+25q=345--------------------because the total value of both the coins is 345 cents \n" ); document.write( "d=q+3--------------------------because there are 3 more dimes than quarters\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Plug d into the first equation \n" ); document.write( "10(q+3)+25q=345\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Distribute \n" ); document.write( "10q+30+25q=345\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Combine like terms \n" ); document.write( "35q+30=345\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Subtract 30 from both sides \n" ); document.write( "35q=315\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Divide both sides by 35 \n" ); document.write( "q=9\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Number of quarters=9\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "d=q+3 \n" ); document.write( "d=9+3 \n" ); document.write( "d=12\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "number of dimes=12\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So, \n" ); document.write( "number or quarters=9 \n" ); document.write( "number of dimes=12 \n" ); document.write( " |