document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=148959>Question 148959</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do you find out the slope of a line with the equation 2x+3y+6=0? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #109294 by </B><A HREF=/tutors/aboutme.mpl?userid=mangopeeler07><B>mangopeeler07(462)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mangopeeler07><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=109294\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x+3y+6=0\r<BR>\n" );
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document.write( "First isolate y<BR>\n" );
document.write( "Move 2x and 6 to the other side:<BR>\n" );
document.write( "3y=-2x-6\r<BR>\n" );
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document.write( "Divide it all by 3<BR>\n" );
document.write( "y=-2/3x-2\r<BR>\n" );
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document.write( "y=mx+b, where m is the slope<BR>\n" );
document.write( "-2/3 takes the place of m in <BR>\n" );
document.write( "y=-2/3x-2\r<BR>\n" );
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document.write( "so slope= -2/3 </SPAN>\n" );
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