document.write( "Question 22383: Explain each step involved in using the 'ac' method to factor the following:
\n" ); document.write( "8x^2 + 2x - 3
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Algebra.Com's Answer #10928 by Alwayscheerful(414)\"\" \"About 
You can put this solution on YOUR website!
First you need to set the equation to 0 so you get a quadratic
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"8x%5E2%2B2x%2B-3+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%282%29%5E2-4%2A8%2A-3=100\".
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\n" ); document.write( " Discriminant d=100 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-2%2B-sqrt%28+100+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%282%29%2Bsqrt%28+100+%29%29%2F2%5C8+=+0.5\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%282%29-sqrt%28+100+%29%29%2F2%5C8+=+-0.75\"
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\n" ); document.write( " Quadratic expression \"8x%5E2%2B2x%2B-3\" can be factored:
\n" ); document.write( " \"8x%5E2%2B2x%2B-3+=+8%28x-0.5%29%2A%28x--0.75%29\"
\n" ); document.write( " Again, the answer is: 0.5, -0.75.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+8%2Ax%5E2%2B2%2Ax%2B-3+%29\"

\n" ); document.write( "\n" ); document.write( "Hope this helps!
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