document.write( "Question 148935: Find three consecutive positive integers such that the product of the first and third, minus the second, is 1 more than 4 times the third. \n" ); document.write( "
Algebra.Com's Answer #109275 by checkley77(12844)\"\" \"About 
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LET X BE THE FIRST NTEGER, (X+1) BE THE SECOND & 9X+2) BE THE THIRD.
\n" ); document.write( "X(X+2)-(X+1)=4(X+2)+1
\n" ); document.write( "X^2+2X-X-1=4X+8+1
\n" ); document.write( "X^2+2X-X-4X-1-8-1=0
\n" ); document.write( "X^2-3X-10=0
\n" ); document.write( "(X-5)(X+2)=0
\n" ); document.write( "X-5=0
\n" ); document.write( "X=5 ANSWER FOR THE FIRST INTEGER.
\n" ); document.write( "5+1=6 THE SECOND.
\n" ); document.write( "5+2=7 THE THIRD.
\n" ); document.write( "PROOF:
\n" ); document.write( "5*7-6=4*7+1
\n" ); document.write( "35-6=28+1
\n" ); document.write( "29=29\r
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