document.write( "Question 148935: Find three consecutive positive integers such that the product of the first and third, minus the second, is 1 more than 4 times the third. \n" ); document.write( "
Algebra.Com's Answer #109274 by ankor@dixie-net.com(22740)\"\" \"About 
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Find three consecutive positive integers such that the product of the first and third, minus the second, is 1 more than 4 times the third.
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\n" ); document.write( "Let the three consecutive numbers be x, (x+1), (x+2)
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\n" ); document.write( "Write an equation for this statement:
\n" ); document.write( "\"product of the first and third, minus the second,is 1 more than 4 times the third.\"
\n" ); document.write( "x(x+2) - (x+1) = 4(x+2) + 1
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\n" ); document.write( "x^2 + 2x - x - 1 = 4x + 8 + 1
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\n" ); document.write( "x^2 + x -1 = 4x + 9
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\n" ); document.write( "Arrange as a quadratic equation on the left
\n" ); document.write( "x^2 + x - 4x - 1 - 9 = 0
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\n" ); document.write( "x^2 - 3x - 10 = 0
\n" ); document.write( "Factors to:
\n" ); document.write( "(x-5)(x+2) = 0
\n" ); document.write( "Positive solution wanted
\n" ); document.write( "x = +5, 6, 7 are the 3 numbers
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\n" ); document.write( "Check solution in the statement
\n" ); document.write( "\"product of the first and third, minus the second,is 1 more than 4 times the third.\"
\n" ); document.write( "5*7 - 6 = 4(7) + 1
\n" ); document.write( "35 - 6 = 28 + 1 \n" ); document.write( "
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