document.write( "Question 148843: Verify the identity using multiple-angle formulas.
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document.write( "1a) cos^(2)3x-sin^(2)3x=cos6x
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document.write( "1b) (sin^(2)2α)/(sin^(2)α)=4-4sin^(2)α \n" );
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Algebra.Com's Answer #109258 by Nate(3500)![]() ![]() ![]() You can put this solution on YOUR website! cos^2(3x) - sin^2(3x) = cos(6x) \n" ); document.write( "cos^2(3x) - sin^2(3x) = cos(3x + 3x) \n" ); document.write( "cos^2(3x) - sin^2(3x) = cos(3x)cos(3x) - sin(3x)sin(3x) \n" ); document.write( "~ \n" ); document.write( "sin^2(2α) / sin^2(α) = 4 - 4sin^2(α) \n" ); document.write( "sin(2α)sin(2α) / sin^2(α) = 4 - 4sin^2(α) \n" ); document.write( "2sin(α)cos(α)2sin(α)cos(α) / sin^2(α) = 4 - 4sin^2(α) \n" ); document.write( "4cos^2(α) = 4 - 4sin^2(α) \n" ); document.write( "4(1 - sin^2(α)) = 4 - 4sin^2(α) \n" ); document.write( " |