document.write( "Question 148915: cashews sell for $5 per pound and peanuts sell for $2 per pound. How many pounds of each would you use to make 21 pounds of a mixture that sells for $3.00 per pound? \n" ); document.write( "
Algebra.Com's Answer #109240 by mangopeeler07(462)\"\" \"About 
You can put this solution on YOUR website!
x=# pounds of cashews
\n" ); document.write( "y=# pounds of peanuts\r
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\n" ); document.write( "\n" ); document.write( "5x+2y=63--------------Because the cost of it all is 21 times 3 (21 pounds of a mixture that sells for $3.00 per pound)\r
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\n" ); document.write( "\n" ); document.write( "x+y=21\r
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\n" ); document.write( "\n" ); document.write( "So you have two equations
\n" ); document.write( "5x+2y=63
\n" ); document.write( "x+y=21\r
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\n" ); document.write( "\n" ); document.write( "Solve for x in the second equation
\n" ); document.write( "x=21-y\r
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\n" ); document.write( "\n" ); document.write( "Plug that into the first equation
\n" ); document.write( "5(21-y)+2y=63\r
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\n" ); document.write( "\n" ); document.write( "Distribute
\n" ); document.write( "105-5y+2y=63\r
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\n" ); document.write( "\n" ); document.write( "Combine like terms
\n" ); document.write( "105-3y=63\r
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\n" ); document.write( "\n" ); document.write( "Subtract 105 from both sides
\n" ); document.write( "-3y=-42\r
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\n" ); document.write( "\n" ); document.write( "Divide by -3
\n" ); document.write( "y=14\r
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\n" ); document.write( "\n" ); document.write( "That is the pounds of peanuts
\n" ); document.write( "plug that into the second equation
\n" ); document.write( "x+14=21\r
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\n" ); document.write( "\n" ); document.write( "Subtract 14 from both sides
\n" ); document.write( "x=7\r
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\n" ); document.write( "\n" ); document.write( "That is the pounds of cashews
\n" ); document.write( "So,\r
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\n" ); document.write( "\n" ); document.write( "14 lbs. peanuts
\n" ); document.write( "7 lbs. cashews
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