document.write( "Question 148879This question is from textbook Elementary and Intermediate Algebra
\n" ); document.write( ": Use grouping to factor each polynomial completely.
\n" ); document.write( "\"x%5E3+%2B+a%2Ax+%2B+3%2Aa+%2B+3%2Ax%5E2\"
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Algebra.Com's Answer #109210 by epylar(1)\"\" \"About 
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Note that \"x%5E3+=+x%5E2%2Ax\".
\n" ); document.write( "From the original expression:\r
\n" ); document.write( "\n" ); document.write( "The expressions \"x%5E3\" and \"3%2Ax%5E2\" have a term \"x%5E2\" which can be factored out. The expressions \"a%2Ax\" and \"3%2Aa\" have a term \"a\" which can be factored out.\r
\n" ); document.write( "\n" ); document.write( "So we have:
\n" ); document.write( "\"x%5E2%2Ax+%2B+a%2Ax+%2B+a%2A3+%2B+x%5E2%2A3\" =
\n" ); document.write( "\"x%5E2%2Ax+%2B+x%5E2%2A3+%2B+a%2Ax+%2B+a%2A3\" =
\n" ); document.write( "\"x%5E2%2A%28x%2B3%29+%2B+a%2A%28x%2B3%29\" =
\n" ); document.write( "\"%28x%5E2+%2B+a%29+%2A+%28x+%2B+3%29\" (answer)
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