document.write( "Question 148805: Pls. help me with this. There are so many given I don't know what to do with all of it or what to use.\r
\n" ); document.write( "\n" ); document.write( "A drag racer accelerates uniformly from rest straight track at 12m/s^2 for 5.5s, maintains the speed it has reached for 3.0s, and slows down to a stop at the rate of -14m/s^2. What is the total distance traveled by the racer?
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Algebra.Com's Answer #109135 by vleith(2983)\"\" \"About 
You can put this solution on YOUR website!
The easiest way to approach this is to look at it as three steps of a bigger problem.\r
\n" ); document.write( "\n" ); document.write( "The general formula that relates distance to acceleration and speed is
\n" ); document.write( "\"d%5Bt%5D=+%28a%2F2%29t%5E2+%2B+v%5B0%5Dt+%2B+d%5B0%5D\" where a is acceleration, v[0] is initial velocity and d[0] is initial position. \r
\n" ); document.write( "\n" ); document.write( "It is also helpful to know that velocity is related to acceleration as follows:
\n" ); document.write( "\"v%5Bt%5D+=+at+%2B+v%5B0%5D\"\r
\n" ); document.write( "\n" ); document.write( "So let's do this problem in three pieces.\r
\n" ); document.write( "\n" ); document.write( "1 - A drag racer accelerates uniformly from rest straight track at 12m/s^2 for 5.5s.\r
\n" ); document.write( "\n" ); document.write( "\"d%5Bt%5D+=+%28a%2F2%29t%5E2+%2B+v%5B0%5Dt+%2B+d%5B0%5D\"
\n" ); document.write( "\"d%5B5.5%5D+=+6%285.5%29%5E2+%2B+0%2A5.5+%2B+0+\"
\n" ); document.write( "\"d%5B5.5%5D+=+181.5+m\" This problem is nice because the units do not require any conversion (you are given acceleration in m/s^2 and time in seconds)\r
\n" ); document.write( "\n" ); document.write( "Let's find our speed at the end of 5.5 seconds
\n" ); document.write( "\"v%5Bt%5D+=+at+%2B+v%5B0%5D\"
\n" ); document.write( "\"v%5B5.5%5D+=+12%2A5+%2B+0+\"
\n" ); document.write( "\"v%5B5.5%5D+=+60m%2Fs\"\r
\n" ); document.write( "\n" ); document.write( "So at the end of the first leg, we have moved 181.5m and are zipping along at 60m/s\r
\n" ); document.write( "\n" ); document.write( "Now let's do the second leg as a 'whole new problem'.
\n" ); document.write( "maintains the speed it has reached for 3.0s
\n" ); document.write( "In this leg, the acceleration is 0 and the initial speed is where ended up at the end of the first leg - 60m.s
\n" ); document.write( "For this leg, we'll start our clock over again at 0
\n" ); document.write( "\"d%5Bt%5D=+%28a%2F2%29t%5E2+%2B+v%5B0%5Dt+%2B+d%5B0%5D\"
\n" ); document.write( "\"d%5B3%5D+=+0%2A3%5E2+%2B+60%2A3+%2B+0%2At\"
\n" ); document.write( "\"d%5B3%5D+=+0+%2B+180+%2B+0+\"
\n" ); document.write( "\"d%5B3%5D+=+180m\"
\n" ); document.write( "Now, we could have gotten more complicated and setup the equation to use to use the same clock as first leg, but that requires getting a lot more complex about where we are, what time it is, etc. More trouble than it is worth. \r
\n" ); document.write( "\n" ); document.write( "For now, just remember that we broke this problem into three small parts. And we will need to put humpty back together again in order to get a 'final answer'.\r
\n" ); document.write( "\n" ); document.write( "Ok, so we are at the end of the second leg. Let's see where we are now and see how fast we are going.\r
\n" ); document.write( "\n" ); document.write( "Our position is the sum of the first two legs. Our time is the sum of the first two leg's times.
\n" ); document.write( "Time at the end of the second leg is 5.5+3 = 8.5 seconds
\n" ); document.write( "\"d%5B8.5%5D+=+distanceLeg1+%2B+distanceLeg2\"
\n" ); document.write( "\"d%5B8.5%5D+=+181.5+%2B+180\"=
\n" ); document.write( "\"d%5B8.5%5D+=+361.5m\"\r
\n" ); document.write( "\n" ); document.write( "Now we are ready for the last leg. At the end of 8.5 seconds, we are still going 60m/s since we did not change speeds on the second leg. We are 361 meters down the road.\r
\n" ); document.write( "\n" ); document.write( "Now we are told to -- slow down to a stop at the rate of -14m/s^2.
\n" ); document.write( "Again, let's treat this as a small standalone problem.
\n" ); document.write( "First, we need to figure out how long it takes to stop.
\n" ); document.write( "\"v%5Bt%5D+=+at+%2B+v%5B0%5D\"
\n" ); document.write( "\"0+=+-14t+%2B+60\"
\n" ); document.write( "\"-60%2F-14+=+t\"
\n" ); document.write( "\"30%2F7+=+t\"
\n" ); document.write( "So it takes about 4.3 seconds to stop.
\n" ); document.write( "\"d%5Bt%5D+=+%28a%2F2%29t%5E2+%2B+v%5B0%5Dt+%2B+d%5B0%5D\"
\n" ); document.write( "\"d%5B4.3%5D+=+-7%284.3%29%5E2+%2B+60%2A4.3+%2B+0\"
\n" ); document.write( "\"d%5B4.3%5D+=+-129.43+%2B+258\"
\n" ); document.write( "\"d%5B4.3%5D+=+128.57m\"\r
\n" ); document.write( "\n" ); document.write( "So add in the distance from the last leg to the total so far to get:
\n" ); document.write( "TotalDistance = 361.5 + 128.57
\n" ); document.write( "TotalDistance is approximately 490m\r
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