document.write( "Question 148805: Pls. help me with this. There are so many given I don't know what to do with all of it or what to use.\r
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document.write( "A drag racer accelerates uniformly from rest straight track at 12m/s^2 for 5.5s, maintains the speed it has reached for 3.0s, and slows down to a stop at the rate of -14m/s^2. What is the total distance traveled by the racer? \n" );
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Algebra.Com's Answer #109135 by vleith(2983) ![]() You can put this solution on YOUR website! The easiest way to approach this is to look at it as three steps of a bigger problem.\r \n" ); document.write( "\n" ); document.write( "The general formula that relates distance to acceleration and speed is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "It is also helpful to know that velocity is related to acceleration as follows: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So let's do this problem in three pieces.\r \n" ); document.write( "\n" ); document.write( "1 - A drag racer accelerates uniformly from rest straight track at 12m/s^2 for 5.5s.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let's find our speed at the end of 5.5 seconds \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So at the end of the first leg, we have moved 181.5m and are zipping along at 60m/s\r \n" ); document.write( "\n" ); document.write( "Now let's do the second leg as a 'whole new problem'. \n" ); document.write( "maintains the speed it has reached for 3.0s \n" ); document.write( "In this leg, the acceleration is 0 and the initial speed is where ended up at the end of the first leg - 60m.s \n" ); document.write( "For this leg, we'll start our clock over again at 0 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Now, we could have gotten more complicated and setup the equation to use to use the same clock as first leg, but that requires getting a lot more complex about where we are, what time it is, etc. More trouble than it is worth. \r \n" ); document.write( "\n" ); document.write( "For now, just remember that we broke this problem into three small parts. And we will need to put humpty back together again in order to get a 'final answer'.\r \n" ); document.write( "\n" ); document.write( "Ok, so we are at the end of the second leg. Let's see where we are now and see how fast we are going.\r \n" ); document.write( "\n" ); document.write( "Our position is the sum of the first two legs. Our time is the sum of the first two leg's times. \n" ); document.write( "Time at the end of the second leg is 5.5+3 = 8.5 seconds \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now we are ready for the last leg. At the end of 8.5 seconds, we are still going 60m/s since we did not change speeds on the second leg. We are 361 meters down the road.\r \n" ); document.write( "\n" ); document.write( "Now we are told to -- slow down to a stop at the rate of -14m/s^2. \n" ); document.write( "Again, let's treat this as a small standalone problem. \n" ); document.write( "First, we need to figure out how long it takes to stop. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So it takes about 4.3 seconds to stop. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So add in the distance from the last leg to the total so far to get: \n" ); document.write( "TotalDistance = 361.5 + 128.57 \n" ); document.write( "TotalDistance is approximately 490m\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |