document.write( "Question 148801: I each dimension of room is increased one meter, the area is increased by 51 meters; and if the length is increased one meter and the width diminished by one meter, the area is decreased three square meters. Find the dimensions of the room? \n" ); document.write( "
Algebra.Com's Answer #109132 by oscargut(2103)\"\" \"About 
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length of the room = x
\n" ); document.write( "width of the room = y
\n" ); document.write( "If each dimension of room is increased one meter, the area is increased by 51 meters\r
\n" ); document.write( "\n" ); document.write( "then (x+1)(y+1)=xy+51\r
\n" ); document.write( "\n" ); document.write( "if the length is increased one meter and the width diminished by one meter, the area is decreased three square meters\r
\n" ); document.write( "\n" ); document.write( "(x+1)(y-1)=xy-3 so equations are:\r
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\n" ); document.write( "\n" ); document.write( "(x+1)(y+1)=xy+51
\n" ); document.write( "(x+1)(y-1)=xy-3\r
\n" ); document.write( "\n" ); document.write( "xy+x+y+1=xy+51
\n" ); document.write( "xy-x+y-1=xy-3\r
\n" ); document.write( "\n" ); document.write( "x+y+1=51
\n" ); document.write( "-x+y-1=-3\r
\n" ); document.write( "\n" ); document.write( "adding equations\r
\n" ); document.write( "\n" ); document.write( "2y=48 then y=24\r
\n" ); document.write( "\n" ); document.write( "x+24+1=51 then x+25=51 then x=26\r
\n" ); document.write( "\n" ); document.write( "Answer:Length=26 meters and width=24 meters\r
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