document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=148784>Question 148784</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve: \r<BR>\n" );
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document.write( "An angle measures 14° less than three times its complement.  <BR>\n" );
document.write( "Find the measure of the angle and it's complement.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #109127 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=109127\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two angles are \"complementary\" if they total to 90 deg.<BR>\n" );
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document.write( "An angle measures 14° less than three times its complement.  <BR>\n" );
document.write( "Find the measure of the angle and it's complement.<BR>\n" );
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document.write( "Let x = angle<BR>\n" );
document.write( "90-x = complement of x<BR>\n" );
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document.write( "x = 3(90-x)-14<BR>\n" );
document.write( "x = 270 - 3x -14<BR>\n" );
document.write( "x = 256 - 3x<BR>\n" );
document.write( "4x = 256<BR>\n" );
document.write( "x = 64<BR>\n" );
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document.write( "90-64 = 26<BR>\n" );
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document.write( "The two angles are 64 and 26 </SPAN>\n" );
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