document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=148394>Question 148394</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a rectangular sheet of paper is 20.5 cm wide. when it is folded in half,  with the crease running parallel to the 20.5 cm sides, the resulting rectangle is the same shape as the unfolded sheet. Find the length of the sheet, to the nearest tenth of a cm. (in Europe, the shape of notebook paper is determined by this similarity property.) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #109126 by </B><A HREF=/tutors/aboutme.mpl?userid=oscargut><B>oscargut(2103)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oscargut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=oscargut><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=109126\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x=length of the original paper<BR>\n" );
document.write( "20.5=wide of the original paper\r<BR>\n" );
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document.write( "20.5=length of the 2nd paper<BR>\n" );
document.write( "x/2=wide of the 2nd paper\r<BR>\n" );
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document.write( "the proportion between the sides are the same so<BR>\n" );
document.write( "20.5/x = (x/2)/20.5\r<BR>\n" );
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document.write( "20.5/x=x/41\r<BR>\n" );
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document.write( "(20.5)41=x^2<BR>\n" );
document.write( "x=sqrt(840.5)=29 (aprox) </SPAN>\n" );
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