document.write( "Question 148764: A rectangular parking lot is 50 ft longer than it is wide. Determine the dimensions of the parking lot if it measures 250 ft diagonally.
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Algebra.Com's Answer #109109 by nerdybill(7384)\"\" \"About 
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A rectangular parking lot is 50 ft longer than it is wide. Determine the dimensions of the parking lot if it measures 250 ft diagonally.
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\n" ); document.write( "Let w = width of parking lot
\n" ); document.write( "then
\n" ); document.write( "w+50 = length of parking lot
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\n" ); document.write( "Using Pythagorean theorem:
\n" ); document.write( "w^2 + (w+50)^2 = 250^2
\n" ); document.write( "w^2 + (w^2 + 100w + 2500) = 62500
\n" ); document.write( "2w^2 + 100w + 2500 = 62500
\n" ); document.write( "2w^2 + 100w - 60000 = 0
\n" ); document.write( "w^2 + 50w - 30000 = 0
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\n" ); document.write( "If it is too difficult factor, use the \"quadratic equation\".
\n" ); document.write( "You'll get two solutions:
\n" ); document.write( "150, -200
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\n" ); document.write( "since it can't negative:
\n" ); document.write( "width=150 ft
\n" ); document.write( "length = 200 ft
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B50x%2B-30000+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%2850%29%5E2-4%2A1%2A-30000=122500\".
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\n" ); document.write( " Discriminant d=122500 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-50%2B-sqrt%28+122500+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%2850%29%2Bsqrt%28+122500+%29%29%2F2%5C1+=+150\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%2850%29-sqrt%28+122500+%29%29%2F2%5C1+=+-200\"
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\n" ); document.write( " Quadratic expression \"1x%5E2%2B50x%2B-30000\" can be factored:
\n" ); document.write( " \"1x%5E2%2B50x%2B-30000+=+1%28x-150%29%2A%28x--200%29\"
\n" ); document.write( " Again, the answer is: 150, -200.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B50%2Ax%2B-30000+%29\"

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