document.write( "Question 148759: Smith bicycled 45 miles going east from Durango and Jones bicycled 70 miles. Jones averaged 5 miles per hour more than Smith and his trip took ½ hour longer than Smith’s. How fast was each one travelling? \n" ); document.write( "
Algebra.Com's Answer #109103 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Smith bicycled 45 miles going east from Durango \n" ); document.write( "Smith DATA: \n" ); document.write( "distance = 45 miles ; rate = x mph : time = d/r = 45/x hrs. \n" ); document.write( " and Jones bicycled 70 miles. \n" ); document.write( "Jones DATA: \n" ); document.write( "distance = 70 miles ; rate = (x+5) mph ; time = d/r = 70/(x+5) hrs. \n" ); document.write( "Jones averaged 5 miles per hour more than Smith and his trip took ½ hour longer than Smith’s. \n" ); document.write( "How fast was each one traveling? \n" ); document.write( "EQUATION: \n" ); document.write( "Jones time - Smith time = 1/2 \n" ); document.write( "45/x - 70/(x+5) = 1/2 \n" ); document.write( "90(x+5) - 140x = x^2+5x \n" ); document.write( "-50x + 450 = x^2 + 5x \n" ); document.write( "x^2 + 60x - 450 = 0 \n" ); document.write( "x = [-60 +-sqrt(60^2-4*-450)]/2 \n" ); document.write( "x = [-60 +- sqrt(5400)]/2 \n" ); document.write( "Positive Solution \n" ); document.write( "x = (-60+ 73.48)/2 \n" ); document.write( "x = 13.48/2 = 6.74 mph (Smith's rate) \n" ); document.write( "x+5 = 11.74 mph (Jones's rate) \n" ); document.write( "========================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------------------ \n" ); document.write( " |