document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=148729>Question 148729</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The problem is to solve the quadratic equation using the Indian method of multiplying each term in the equation by four times the coefficient of the <BR>\n" );
document.write( "x sqrt 2 term.<BR>\n" );
document.write( "The equation is:   x^ - 2x - 13 = 0<BR>\n" );
document.write( "I am totally stumped. Please help.\r<BR>\n" );
document.write( "\n" );
document.write( "Ellen </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #109079 by </B><A HREF=/tutors/aboutme.mpl?userid=oscargut><B>oscargut(2103)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oscargut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=oscargut><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=109079\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x^2 - 2x - 13 = 0\r<BR>\n" );
document.write( "\n" );
document.write( "x^2 - 2x =13\r<BR>\n" );
document.write( "\n" );
document.write( "4x^2-8x=52\r<BR>\n" );
document.write( "\n" );
document.write( "4x^2-8x+4=56<BR>\n" );
document.write( "(2x-2)^2=56<BR>\n" );
document.write( "2x-2=sqrt(56) or 2x-2=-sqrt(56)<BR>\n" );
document.write( "x=(sqrt(56)+2)/2 or x=(-sqrt(56)+2)/2 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );